**Q: Find all solutions for X where 0 < X < 360 degrees and 9*cos(X) – 5 = 0.**

Answer:

Okay, the 0 < X < 360 just tells you we are looking for answers in one complete circle (no more, no less).

So, we first need to solve for X like so:

**9*cos(X) – 5 = 0**

9*cos(X) = 5

cos(X) = 5/9

X = cos^{-1}(5/9)

Plug this into your calculator and you get:

X = 56.25 degrees

This is part of your answer, but not all of it.

So, next, since, from our problem, we saw that:

cos(X) = 5/9

this means that the cosine value is positive. In what quadrants are the cosine values positive??

Quadrant 1 and Quadrant 4 have positive cosine values. Therefore, there will be 2 answers (one in each quadrant).

So, X = 56.25 degrees is the answer for the angle in Quadrant 1.

To get the angle in Quadrant 4 that also works, you gotta do 360 – 56.25 = 303.75

Therefore, 303.75 degrees is another answer for X.

What this is saying is that:

cos(56.25)= 5/9 **and **cos(303.75) = 5/9 also.

So, X = 56.25 **and **303.75

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